Question

two die rolled simultaneously.find the probability of getting doubler.​

Answer 1

Answer:

Step-by-step explanation:

Hi friend,

Total outcomes when rolling 2 dice =36

Probability of getting doublet=P(A)= { (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)}=6/36

Probability of getting  sum as 6=P(B)={ (1,5) (2,4) (3,3) (4,2) (5,1)}=5/36

Probability of getting both sum as 6 and also a doublet =P(A∩B)={(3,3)}=1/36

So,probability of getting a doublet or a total of 6 is calculated using addition theorem of probability

P(A∪B)=P(A)+P(B)-P(A∩B)

           =6/36+5/36-1/35=11/36-1/36=10/36=5/18

HOPE THIS HELPS.....

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Answer 2

Answer:

Total outcomes when rolling 2 dice = 36

probability of getting doublet = P(A)={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6/36

probability of getting sum as 6=P(B)=

{(1,5),(2,4),(3,3),(4,2),(5,1)}=5/36

probability of getting a doublet and

total of 6 is P(A∩B)={(3,3)}=1/36

probability of getting a doublet or a

total of 6=P(A∪B)=P(A)+P(B)−P(A∩B)

=6/36+5/36−1/36

=10/36=5/18

Answer:5/18

Step-by-step explanation:

Hope this answer will be helpful..