Question

Two dies are rolled what is the probability that they show different phases

Answer 1

Hey There!!!!

Answer Of Your Question {:

If We Roll 2 dies,There Are (1,1),(2,1),(3,1),(4,1),(5,1)(6,1),(2,1),...................(6,6)

Means The Equation Is=(6×6)=(6)^2

Let's Think Any One Probability Of Getting Different Number=A

Then,A Can Be =(6×5) 【Note:-We Can't Put Another 6】

So , According To Formula,

P(A)=6×5/36

→P(A)=30/36

→P(A)=5/6

Hope My Answer Helped☺️