two dies are thrown simultaneously find the probability that sum of faces of dise is 8
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Answer:
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Answered by
0
Answer:
5/36
Step-by-step explanation:
given
two dices are thrown
total no of outcomes n(S)==36
sum of faces is 8
no of possible outcomes =n(A)=
(2,6),(3,5),(4,4),(5,3),(2,6)
n(A)=5
probability=no of possible outcomes/total no of outcomes
p(A)=n(A)/n(S)
=5/36
p(A)=5/36
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