two diff dice are tossed find the probability
i]getting a doublet
ii]sum 10
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s = { 11, 12 ,13 ,14 15, 16
21,22,23,24,25,26
31,32,33,34,35,36
41,42,43,44,45,46
51,52,53,54,55,56
61,62,63,64,65,66 }
n(s) = 36
1] take that event as A
A = {11, 22, 33, 44, 55, 66 }
n(A) = 6
p(A) = n(A)/n(s)
p(A) = 6/36
2]take that event as B
B = { 64,55,64}
n(B) = 3
P(B) = n(B)/n(S)
P(B) = 3/36
21,22,23,24,25,26
31,32,33,34,35,36
41,42,43,44,45,46
51,52,53,54,55,56
61,62,63,64,65,66 }
n(s) = 36
1] take that event as A
A = {11, 22, 33, 44, 55, 66 }
n(A) = 6
p(A) = n(A)/n(s)
p(A) = 6/36
2]take that event as B
B = { 64,55,64}
n(B) = 3
P(B) = n(B)/n(S)
P(B) = 3/36
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