Question

Two diff dice are tossed together : find the probability : a) of getting a doublet b) of getting a sum 10 , of the numbers on the two sides .

Answer 1

Hey here is your solution...!!

I hope it will help you......!!

Answer 2

total no of event = 6*6=36
a)  getting doublet = (1,1) (2,2) (3,3)(4,4) (5,5) (6,6) means no of event = 6
so probability =6/36 =1/6

b)  getting 10 =(4,6) (5,5) (6,4) means no of event = 3
probability= 3/36  =1/12