Question

two differemt dice are thrown together find the probability that (1) the sum of the numbers
less than 7

Answer 1

probability (of getting an event)=no of possible outcomes/total no of events


here total no of events=(11,12,13,14,15,16,21,22,23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66)
=36

no of possible outcomes=(11,12,13,14,15,21,22,23,24,31,32,33,41,42,51)
=15/36
=5/12


^_^hope it helps uhh....if uhh r satisfied thn plzzzz mrk it as brainliest ans....thank you ....

Answer 2

Number of favourable outcomes =15
Total number of outcomes =36
Therefore probability ,
15/36=5/12

Therefore 5/12 is the answer