Question

Two different coins are tossed randomly find the probability of 1) getting at least 1 head

Answer 1

Answer:

Total no. cases = 4(HH, TT, HT, TH)

Favourable cases = 3(HH, HT, TH)

Probability = ¾

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Answer 2

Answer:

When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.

Therefore, total numbers of outcome are 22 = 4

Step-by-step explanation: