Question

Two different coins are tossed simultaneously the probability of getting at least one head is

Answer 1

S = { HH, HT, TH, TT }

n ( S ) = 4

Event A says that getting at least one head.

So, A = { HH, HT, TH }

n ( A ) = 3

Now, let us calculate its probability!

P ( A ) = n ( S ) / n ( A )

= 3 / 4

Hence, the probability of getting at least one head is 3/4.

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Answer 2

Step-by-step explanation:

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