two different coins are tossed together find the probability of (i) getting a doublet (ii) of getting a sum 10,of the numbers on two dice
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(i) total outcomes = 36
Favourable outcomes = (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
=6
P(E) = 6/36
= 1/6
(ii) total outcomes= 36
Favourable outcomes = (4,6) (5,5) (6,4)
= 3
P(E) = 3/36
= 1/12
Favourable outcomes = (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
=6
P(E) = 6/36
= 1/6
(ii) total outcomes= 36
Favourable outcomes = (4,6) (5,5) (6,4)
= 3
P(E) = 3/36
= 1/12
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