Question

Two different containers A & B are filled with two different liquids of equal mases.The level of the liquid in container A is found to be one-fourth of the level in container B.What is the ratio of densities of two liquids?If the liquid in container A is 2 g. cm.³ ,then find the density of the mixture.​

Answer 1

Explanation:

Mass of liquid A, (mA) = mass of liquid B, (mB)

Volume = area×height

Area of cross section of A = Area cross section of B

Height of liquid column A = 14× " height " of liquid column A = 14 (Volume of B) Densityof"mass/volume"(density " of " A)/(density " of " B) = m_(A)/V_(A)xx V_(B)/m_(B)=V_(B)/V_(B)=4/1=4 :1Ifden

sityofAis2 g cm^(-3),thendensityofB= g cm^(-3)=0.5 g cm^(-3)Densityofmixture="mass of mixture"/"volume of mixture"(m_(A)+m_(B))/(v_(A)+v_(B))=(m_(A)=m_(A))/(v_(A)=4v_(A)) ( :. m_(B) = m_(A) and v_(B)= 4v_(A))(2m_(A))/(5v_(A))

= (2xx d_(A)xx v_(A))/(5V_(A)(2xx2)/5=4/5=0.8 " g "cm^(-3)`

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