Two different dice are thrown at the same time find the probability of getting a)a sum b)sum divisible by 5 c)sum of at least 11
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When two dice are thrown simultaneously, the sample space of the experiment is
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
So there are 36 equally likely outcomes.
Possible number of outcomes =36.
Let E be an event of getting a sum divisible by 5.
Favourable outcomes =(1,4),(2,3),(3,2),(4,1),(4,6),(5,5),(6,4)
Number of favourable outcomes =7
P(E)=7/36
Probability of getting a sum divisible by 5 is 7/36.
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