Question

two different dice are thrown together.find the probability that must the number obtained have i)even sum,and ii) even product.

Answer 1

solution :-

Total no. of outcomes = 36 .

( 1,1) ( 1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5)(2,6)
(3,1) (3,2)( 3,3)(3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)


1) Total no. of outcomes = 36.

Favourable no. of outcomes = 18.

probability = Total no. of favourable outcomes / Total no. of possible outcomes.

therefore, probability of getting an even sum = 18/ 36
=1 /2ans.

2) Total no. of outcomes = 36.

Favourable no. of outcomes = 27.

probability = Total no. of favourable outcomes / Total no. of possible outcomes.

therefore, probability of getting an even product = 27/ 36
= 3/4ans.

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