Question

Two different dice are thrown together, find the probability that the sum
of the numbers appeared is less than 5.​

Answer 1

Step-by-step explanation:

Sample space : (11.12.13.14.15.16.21.22.23.24.25.26.31.32

33.34.35.36.41.42.43.44.45.46.51.52.53

.54.55.56.61.62.63.64.65.66)

n(s)=36

EVENT A: SUM OF TWO NO IS LESS THAN 5

A:(11.12.13.21.22.31.)

n(a)=6

p(a)=n(a)/n(s)

=6/36

=1/6

therefore probability of getting sum less than 5 is 1/6