Two different dice are thrown together find the probability of 1) getting a doubled 2) getting a sum 10, of the no. On the two dice
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1) elements are (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
P(e) = 6/36 =1/6
2)elements are (4,6) (5,5) (6,4)
P(e) = 3/36 =1/12
P(e) = 6/36 =1/6
2)elements are (4,6) (5,5) (6,4)
P(e) = 3/36 =1/12
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