Question

two different dice are thrown together. find the probability that the numbers obtained have a product less than 16.

Answer 1

Total no. of outcomes = 36
Favourable outcomes = (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (4,1) , (4,2) , (4,3) , (5,1) , (5,2) , (5,3) , (6,1) , (6,2)

= 25

P(E) =
$\frac{25}{36}$