Two different dice are thrown together. Find the probability that the numbers obtained
(i) have a sum less than 7
(ii) have a product less than 16
(iii) is a doublet of odd numbers.
Answers
Answered by
269
Answer:
Step-by-step explanation:
toTAl no. 0F outcomes=36
Sum less than 7 means ex:1+2 in 2 dice(1+3)(1+4)....
No of it=15
P=15/36
No of outcomes product less than 16
=25 eg(1,1)(2,2)(2,3).......
P=25/36
P that it is doublet of odd no=9/36=1/4
Eg=1-1,3-1,5-1,1-3,3-3,5-3,1-5,3-5,5-5
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Answered by
10
Answer:
15/36=5/12
25/36
9/36=1/4
please mark me brainliest
Step-by-step explanation:
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