Math, asked by richwitch5642, 1 year ago

Two different dice are thrown together. Find the probability that the numbers obtained
(i) have a sum less than 7
(ii) have a product less than 16
(iii) is a doublet of odd numbers.

Answers

Answered by dorgan399
269

Answer:


Step-by-step explanation:

toTAl no. 0F outcomes=36

Sum less than 7 means ex:1+2 in 2 dice(1+3)(1+4)....

No of it=15

P=15/36

No of outcomes product less than 16

=25 eg(1,1)(2,2)(2,3).......

P=25/36

P that it is doublet of odd no=9/36=1/4

Eg=1-1,3-1,5-1,1-3,3-3,5-3,1-5,3-5,5-5


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Answered by kampallipallavi
10

Answer:

15/36=5/12

25/36

9/36=1/4

please mark me brainliest

Step-by-step explanation:

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