two different dice are thrown together . find the probability of getting
[1] of getting a doublet
[2] of getting a sum of 10
of the number on the two dice
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total no. of possible outcomes=36
1)fav. cases(getting a doublet)=6
probability=6/36
2)fav. cases(getting a sum of 10)=3
probability=3/36
=1/12
1)fav. cases(getting a doublet)=6
probability=6/36
2)fav. cases(getting a sum of 10)=3
probability=3/36
=1/12
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