Question

"Two different dice are thrown together. Find the probability of:
(i) getting a number greater than 3 on each die
(ii) getting a total of 6 or 7 of the numbers on two dice"

Answer 1

Answer:

This can be solved in a simple way.

We toss dice twice,

So total no. of outcomes :6*6=36

We need even numbers on both dice.

So possible number of arrangements are

{2,4,6}x{2,4,6}

=3x3

=9 possible combination of even numbers.

Therefore required probability is:9/36=1/4.

I Hope it will help!

^_^

Answer 2

Answer:

Step-by-step explanation:

There are 2 dice:

Total possible outcome = 6 x 6 = 36

Find the probability that getting greater than 3 on each dice

Possible favourable outcome on each dice = 3

(They are 4, 5 and 6)

P(Greater than 3 on each dice ) =( 3 x 3)/36 = 1/4

Find the probability that the sum is 6 or 7:

Possible favourable outcome = 11

They are (1, 5), (1, 6), (2, 4), (2, 5), (3, 3), (3, 4), (4, 2), (4, 3), (5, 1), (5, 2), (6, 1)

P(Sum or 6 or 7) = 11/36

Answer: (i) 1/4 (ii) 11/36