Question

Two different dice are toss together find (i) of getting a double. (ii) of getting sum of 10 no. On the dice ?

Answer 1

Heya !!

Here is your answer..

The outcome of the two dice when tossed together will be ==>

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

(i) We get double six times. The outcomes are ==>

(1,1) ; (2,2) ; (3,3) ; (4,4) ; (5,5) ; (6,6)

So, probability of getting a double is

==> 6/36

==> 1/6

(ii) We get a total of 10 three times.The outcomes are ==>

(4,6) ; (5,5) ; (6,4)

So, probability of getting a total of 10 is

==> 3/36

==> 1/12

Hope it helps.

Answer 2

Hi...✌️✌️

Total number of outcomes = 36

n(S) = 36

{ as 6² = 36 }

Now,

(i) : Event E1: Getting a doublet

i.e., E1 : { (1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6) }

=> n(E1) = 6

Probability ,

P(E1) = n(E1)/n(S)
= 6/36
= 1/6 ___ Ans.

(ii) : Event E2: Getting sum 10

i.e., E2 : { (4,6) , (5,5) , (6,4) }

=> n(E2) = 3

Probability ,

P(E2) = n(E2)/n(S)
= 3/36
= 1/12 ___Ans.

Thank you✌️✌️