Question

two different dice are tossed. find the probability of getting a doublet and of getting a sum of 10, of the no. on the two dice

Answer 1

Two dice are tossed.

What are the possibilities?

1st one can be (1,2,3,4,5,6)

Second dice (1,1) with 1 of first (2,1) with 1 of first.............(6,1) with 1.

Similarly it forms (1,2) with 2 of first .................(6,2) with 2

This will go on till (6,6)

So there are possibilities from(1,1) to (6,6)

From (1,1) to (1,6) there are 6 probabilities.

So from (1,1) to (6,6) there are 6*6 =36 possibilities.

Total possibilities=36

Sums which add up to 10.

only 5+5=10.6+4=10 and 4+6=10

Total favourable outcomes=3

(4,6),(6,4) or (5,5)

P(getting sum of 10)=Total favourable outcomes/Total possibilities

=3/36

=1/12

Probability=1/12

Doublets means same number on both dices.

Getting doublet means these outcomes:

(1,1)(2,2)..........(6,6)

Hence number of possibilities=6

P(doublet)=6/36

=1/6

Probability=1/6

Hope it helps you.