two different dice are tossed. find the probability of getting a doublet and of getting a sum of 10, of the no. on the two dice
Answers
Two dice are tossed.
What are the possibilities?
1st one can be (1,2,3,4,5,6)
Second dice (1,1) with 1 of first (2,1) with 1 of first.............(6,1) with 1.
Similarly it forms (1,2) with 2 of first .................(6,2) with 2
This will go on till (6,6)
So there are possibilities from(1,1) to (6,6)
From (1,1) to (1,6) there are 6 probabilities.
So from (1,1) to (6,6) there are 6*6 =36 possibilities.
Total possibilities=36
Sums which add up to 10.
only 5+5=10.6+4=10 and 4+6=10
Total favourable outcomes=3
(4,6),(6,4) or (5,5)
P(getting sum of 10)=Total favourable outcomes/Total possibilities
=3/36
=1/12
Probability=1/12
Doublets means same number on both dices.
Getting doublet means these outcomes:
(1,1)(2,2)..........(6,6)
Hence number of possibilities=6
P(doublet)=6/36
=1/6
Probability=1/6
Hope it helps you.