Two different dice are tossed together. Find the probability :
(i) of getting a doublet
(ii) of getting a sum 10, of the numbers on the two dice.
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Step-by-step explanation:
Total outcomes = 36
1) prob.of getting a doublet
S={ (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)}
so,
P(of getting a doublet)= 6/36=1/6
2) prob.of sum= 10
S={ (4,6)(6,4)}
P(of getting sum 10)= 2/36=1/18
hope u got the answer
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