Question

Two different dice are tossed together. Find the probability:

i. of getting a doublet

ii. of getting a sum 10, of the numbers on the two dice.

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Answer 1

Answer:

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Step-by-step explanation:

Total number of possible outcomes = 36

i. Doublets are (1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6)

Total number of doublets = 6

∴ Prob (getting a doublet) = 6/36 = 1/6

ii. Favourable outcomes are (4, 6) (5, 5) (6, 4) i.e., 3

∴ Prob (getting a sum 10) = 3/36 = 1/12

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Answer 2

HEY MATE HERE IS YOUR ANSWER:

TOTAL NUMBER OF POSSIBLE OUTCOMES =36

(I) Doublets are (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)

TOTAL NUMBER OF DOUBLETS: 6

: Prob (getting a doublet)= 6/36 = 1/6

(ii) Favoruable outcomes are (4,6) (5,5) (6,5) i.e, 3

:Prob (getting a sum 10) = 3/36 = 1/12

DONE✓✓✓✓✓✓