Question

Two different dice are tossed together find the probability of getting a sum 9 of the numbers on the two dice ​

Answer 1

Answer:

4/36= 1/9

Step-by-step explanation:

No. of favourable outcome = 4 {( 3,6),(4,5),(5,4),(6,3)}

Total no. of outcome = 36

Probability of getting sum 9= no. of favourable outcome

total no. of outcome

= 4/36. =1/9

Answer 2

Question :- If two balanced dice are tossed once, what is the probability of the event that the sum of the integers coming on the upper sides of the two dice is 9 ?

Solution :-

we know that, when two dice are tossed once, then possible events will be

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Total 36 .

so,

→ Total possible events where sum of upper side of the dice is 9 is = (3,6), (4,5), (5,4) and (6,3) = Total 4 .

therefore,

→ Required Probability = Favourable outcomes / Total number of outcomes = 4/36 = (1/9) (Ans.)

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