Question

two different dice are tossed together find the probability. (1)of getting a doubled

Answer 1

Heya !!

Here is your answer..

The outcome for the following is ==>

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

The favourable outcomes are ==>

(1,1) ; (2,2) ; (3,3) ; (4,4) ; (5,5) ; (6,6)

So probability of getting a double is

==> 6/36

==> 1/6

Favourable outcomes for getting a total of 10 ==>

(4,6) ; (5,5) ; (6,4)

Probability of getting a total of 10

==> 3/36

==>1/12

Hope it helps.

Answer 2

Given:

Two dice

To find:

The probability of getting a double

Solution:

Sample space = ( 1, 0 ), ( 1, 1 ), ( 1, 2 )... ( 6, 6 )

Hence,  

Sample space = 36

To find the probability of getting a doublet,

Outcomes = ( 1, 1 ), ( 2, 2 ).. ( 6, 6 )

Possible outcomes = 6

P (getting a double) = 6 / 36  

Hence, P (getting a double) = 1 / 6

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