Question

Two different dice are tossed together. Find the probability (i) of getting a doublet (ii) of getting a sum 10, of the numbers on the two dice.

Answer 1

(i) Probability of getting a doublet = $\frac{6}{36}$

                                                          = $\frac{1}{6}$

(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)

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(ii) Probability  of getting a sum of 10 on two dice = [tex] \frac{3}{36} [/tex]

                                                                                     = $\frac{1}{12}$

(4,6) (6,4) (5,5)
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Answer 2

Given:

Two dice

To find:

The probability of getting a double

The probability of getting a sum of 10

Solution:

Sample space = ( 1, 0 ), ( 1, 1 ), ( 1, 2 )... ( 6, 6 )

Hence,  

Sample space = 36

To find the probability of getting a doublet,

Outcomes = ( 1, 1 ), ( 2, 2 ).. ( 6, 6 )

Possible outcomes = 6

P (getting a double) = 6 / 36  

Hence, P (getting a double) = 1 / 6

To find the probability of getting a sum of 10,

Possible outcomes = ( 4, 6 ), ( 6, 4 ), ( 5, 5 )  

P (getting a sum of 10 ) =3/36

Hence, P ( getting a sum of 10 ) = 1 / 12

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