Question

Two different dice are tossed together..find the probability of getting a doulbe

Answer 1

P(getting a doublet) =6/36=1/6

Answer 2

Heya !!

Here is your answer..

The outcomes will be as following ==>

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Now, outcomes of getting a doublet ==>

(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)

So, Probability

==> 6/36

==> 1/6

Hope it helps.