Question

two different dice are tossed together find the probability i) 5 will not come up on either of them ii) that the sum of number appearing on the two dice is 5 iii) getting same number on both the dice iv) different number on both sides​

Answer 1

Answer:

1  2  3  4  5  6  

1  (1,1) (1,2)  (1,3)  (1,4)  (1,5) (1,6)

2  (2,1) (2,2) (2,3) (2,4) (2,5)  (2,6)  

3  (3,1) (3,2) (3,3) (3,4) (3,5)  (3,6)  

4 (4,1)  (4,2) (4,3) (4,4) (4,5)  (4,6)  

5 (5,1)  (5,2) (5,3) (5,4) (5,5) (5,6)

6 (6,1)  (6,2) (6,3) (6,4) (6,5) (6,6)

(i) Let the event that the number of each die is even.

Favourable outcomes ={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)}

Probabaility that number on each dice is even =  369=  41

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(ii) That the sum of numbers appearing on the two dice is 5.

Favourable outcomes ={(1,4),(2,3),(3,2),(4,1)}

Probability that the sum of the numbers apperaing on the two dice is 5=  

364 =  91

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Step-by-step explanation: