Question

Two different dice are tossed together find the probability that the product of number on the top of the dice is 6

Answer 1

n(s) =36
Number of outcome={(1,6)(6,1)(2,3)(3,2)
=4
Hence P(A)= n(A)/)n(S) = 4/36 = 1/9
Hence,the answer is 1/9
Hoe this solution helps you.... ☺

Answer 2

$\huge\mathbb{SOLUTION:-}$

Two dice are tossed

S = [(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]

Total number of outcomes when two dice are tossed = 6 × 6 = 36

Favourable events of getting product as 6 are:

(1 × 6 = 6),(6 × 1 = 6),(2 × 3 = 6),(3 × 2=6)

i.e. (1,6), (6,1), (2,3), (3,2)

• Favorable events of getting product as 6 = 4.

$\therefore$ P(getting product as 6) = $\frac{4}{36}=\frac{1}{9}$