Question

Two different dice are tossed together find the probability that the productil of the number on the top of the dice is 6

Answer 1

solution :

n(s)=36

number of outcomes ={(1,6)(6,1),(2,3)(3,2)}

=4

Hence P(A)=n(A)n(S)=436=19

Answer : 19

thanks

Answer 2

Answer:

Two dices are thrown no probable chances are

(1, 1); (1, 2); (1, 3); (1, 4); (1, 5); (1, 6)

(2, 1); (2, 2); (2, 3); (2, 4); (2, 5); (2, 6)

(3, 1); (3, 2); (3, 3); (3, 4); (3, 5); (3, 6)

(4, 1); (4, 2); (4, 3); (4, 4); (4, 5); (4, 6)

(5, 1); (5, 2); (5, 3); (5, 4); (5, 5); (5, 6)

(6, 1); (6, 2); (6, 3); (6, 4); (6, 5); (6, 6)

How many sets possible? Yeah it's 36.

Out of these 36 sets, we know product should be 6.

In what cases 6 can be product?

→ 6 × 1, 1 × 6, 2 × 3, 3 × 2

→ (6, 1); (1, 6); (2, 3); (3, 2)

How many time these sets came? Yeah it's 4.

Probability = 4/36 = 1/9

Answer is 1/9