two different dice are tossed together find the probably of getting a double and of getting a sum 10 of the number on the two dice
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6/36= 1/6 is the probability of getting a doublet.
3/36 =1 /12 is the probability of getting a sum of 10.
Hope it helps
3/36 =1 /12 is the probability of getting a sum of 10.
Hope it helps
Answered by
6
11 (¡) of Getting a doublet
(1,1) (2,2) (3,3) (4,4) (5,5) (6,6) = 36
hence, 6/36
= 1/6
(¡¡) sum of 10 of number on the two dice
(6,4) (4,6) (5,5)
hence,. 3/26
=. 1/ 13 ... answer
(1,1) (2,2) (3,3) (4,4) (5,5) (6,6) = 36
hence, 6/36
= 1/6
(¡¡) sum of 10 of number on the two dice
(6,4) (4,6) (5,5)
hence,. 3/26
=. 1/ 13 ... answer
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