Question

Two different dice thrown together. Find the probability of even product

Answer 1

Number of favourable outcomes for even product

                   ( 1 , 2 ) ( 1, 4 ) ( 1 , 6 )
       ( 2 , 1 )  ( 2 , 2 ) ( 2 , 3 ) ( 2 , 4 ) ( 2 , 5 ) ( 2 , 6 )
                   ( 3 , 2 ) ( 3 , 4 ) ( 3 , 6 )
        ( 4 , 1 ) ( 4 , 2 ) ( 4 , 3 ) ( 4 , 4 ) ( 4 , 5 ) ( 4 , 6 )
                   ( 5 , 2 ) ( 5 , 4 ) ( 5 , 6 )
      ( 6 , 1 ) ( 6 , 2 ) ( 6 , 3 ) ( 6 , 4 ) ( 6 , 5 ) ( 6 , 6 )

             P(E)  =   Number of favorable outcomes  
                         Total number of possible outcomes
                      =  27 / 36
                      = 3 / 4.

Answer 2

Sample space:{(0,0) ........ (6,6)}

Favourable outcomes: { (0, 1-6) ; (1, 246) ; (2, 1-6) ; (3, 246) ; (4, 1-6) ; (5, 246) ; (6, 1-6)}

Total number of outcomes: 36

Probability: 27/36 = 3/4