Two different dise tossed together find the probability of geeting doubles and getting a sum of 10 the numbers of two dise
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total no of event = 6*6=36a) getting doublet = (1,1) (2,2) (3,3)(4,4) (5,5) (6,6) means no of event = 6so probability =6/36 =1/6
b) getting 10 =(4,6) (5,5) (6,4) means no of event = 3probability= 3/36 =1/12
b) getting 10 =(4,6) (5,5) (6,4) means no of event = 3probability= 3/36 =1/12
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