Question

two different gases of molecular masses M1 and M2 are at same temperature what is the ratio of their means square feets​

Answer 1

you mean question is -----> two different gases of molecular masses M1 and M2 are at same temperature what is the ratio of their root mean square velocities ?

solution : we know, Root mean square velocity is given by , $v_{rms}=\sqrt{\frac{3RT}{M}}$

where T is temperature of gas and M is molecular mass of gas.

here given, two different gases of molecular $M_1$ and $M_2$ are at same temperature.

so, $\frac{v_{{rms}_1}}{v_{{rms}_2}}=\frac{\sqrt{\frac{3RT}{M_1}}}{\sqrt{\frac{3RT}{M_2}}}$

so, $\frac{v_{{rms}_1}}{v_{{rms}_2}}=\sqrt{\frac{M_2}{M_1}}$