Question

two different liquids are flowing in two tubes of equal radius. the ratio of coefficients of viscosity of liquids is 52:49 and the ratio of their densities is 13:1 then the ratio of their critical velocities will be

Answer 1

The ratio of their critical velocities will be

= 4:49

Given:

Two different liquids are flowing in two tubes of equal radius.

Ratio of coefficients of viscosity of liquids is 52:49

Ratio of their densities is 13:1

To find:

The ratio of their critical velocities will be.

Concept used:

Critical velocity of liquid can be calculated by using Reynolds number = RE

    Re = $\frac{\rho V D}{\mu}$

Where, $\rho$ = density

            V = Critical velocity.

            D = Diameter

            $\mu$ = coefficients of viscosity

Explanation:

In critical velocity Reynolds number equal in both the cases.

So that,

$\frac{\rho_1 V_1 D_1}{\mu_1}$ = $\frac{\rho_2 V_2 D_2}{\mu_2}$  

Radius are equal so that diameter are also equal.

From above equation,

$\frac{V_2}{V_1}$ = $\frac{\rho_2 \mu_1}{\rho_1\mu_2}$ = $\frac{1}{13}$×$\frac{52}{49}$ = 4:49

The ratio of their critical velocities will be = 4:49

To learn more....

1)Write the physical significance of reynolds number

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