Two different masses are determined as (23.7 ± 0.5) g and (17.6 ± 0.3) g. What is the sum of their masses?
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Answer:
The sum of the masses = (41.3 ± 0.8)
Explanation:
As per the given data of the question, we have
Value of first mass = (23.7 ± 0.5) g
Now,
Let this mass be A = (23.7 ± 0.5) g
That is,
A = 23.7 and ΔA = 0.5
Value of other mass = (17.6 ± 0.3) g
Now,
Let this mass be B = (17.6 ± 0.3) g
That is,
B = 17.6 and ΔA = 0.3
Therefore,
Sum of the both masses is written as
Sum = A + B ± ( ΔA + ΔB )
= 23.7 + 17.6 ± ( 0.5 + 0.3 )
= 41.3 ± 0.8
Hence, the sum of the masses = (41.3 ± 0.8)
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