Two different sources of light A and B have wavelength 0.7 μm and 0.3 μm respectively. Then which of the following statement is true
1. Both has equal energy
2. A has greater energy then B
3. None of the above
4. B has greater energy then A
Anonymous:
Is the answer 4?
Answers
Answered by
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Hey deepika,
Accordind to PLANCK-EINSTEIN formula
E=hf
where h is planck's constant
and f is frequency
Since velocity=wavelength×frequency
so frequency=velocity/wavelength
We get E=h×velocity/wavelength
So E is inversely proportional to wavelength
Hence B wave has more energy than A.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
Accordind to PLANCK-EINSTEIN formula
E=hf
where h is planck's constant
and f is frequency
Since velocity=wavelength×frequency
so frequency=velocity/wavelength
We get E=h×velocity/wavelength
So E is inversely proportional to wavelength
Hence B wave has more energy than A.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
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