Question

Two different wires have specific resistivity, lengths, area of cross-section are in the ratio 3 : 4, 2 : 9 and 8 : 27. Then the ratio of resistance of two wires is________.​

Answer 1

Answer:HOPES THIS HELPFUL TO U

Given that

P1

P2

_9

la2

a1 27

a2 8

Where,

p represents the Resistivity of two wires,I

represents the length of two wires and a

represents the area of cross section of two

wires

Now,

second wire be R2

So,

R1/R2 is equal to

plxl1

rl

al

p2x12

r2

a2

rl pl x l1 x a2

=

r2 2x 12 x al

9

8

4

x

27

3

2

16

9

So,

The ratio of their resistances is

16:9

We already know that:

r= Pxl

T=

So,

Let the resistance of first wire be R1 and