Question

Two differet die are thrown together find probability that no.Obtained have sum luss than 7

Answer 1

number of outcomes = 36

(i) Favourable outcomes are

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (2, 1) (2, 2) (2, 3)

(2, 4) (3, 1) (3, 2) (3, 3) (4, 1) (4, 2) (5, 1) i.e., 15

P(sum less than 7) = 15/36 = 5/12

(ii) Favourable outcomes are

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (2, 1) (2, 2) (2, 3)

(2, 4) (2, 5) (2, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (4, 1)

(4, 2) (4, 3) (5, 1) (5, 2) (5, 3) (6, 1) (6, 2) i.e., 25

P(product less than 16) = 25/36

(iii) Favourable outcomes are

(1, 1) (3, 3) (5, 5)

P(doublet of odd number) = 3/36 or 1/12