two digit is such that the product of its digit is 8 ,when 63 is subtracted from the no the digit interchange its place. find the no.
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on sloving both the equation you will get the answer
let the no be 10x+y
let the no be 10x+y
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sudhirmittal80:
This question is correct see,
Let tens place digit =X let ones place digit =y. Then , xy =8. Also , 10x +y-63=10y+X. So, 9(x-y)=63. X-Y =7 ,. But xy=8. Putting value of X (7+y)y = 8 y2 +7y-8. y2 +8y-y-8. y(y+8) -1(y+8). So , y=1 and X=8 which give no 81
ok thanks
my mistake
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I am not sure about this question
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