Question

two digit number is obtained by either multiplying the sum of the digits by 8 and then subtracting 5 by multiplying the difference of digits by 16 and then adding 3 then find the number

Answer 1

Hope it helps...!!

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Let the unit digit and the ten's digit of the number be x and y respectively.


Therefore the number = 10y + x.


Sum of digits = x+y


10y+x=8(x+y)-5

10y+x=8x+8y-5

7x-2y=5-------------(1)


Difference of the digits = y-x [if x < y]


10y+x=16(y-x)+3

10y+x=16y-16x+3

17x-6y=3------------(2)



Multiply eq(1) by 3 and subtracting eq(2):

21x-6y=15

17x-6y=3

4x=12

x=12/4=3



Substitute x =3 in eq(1):

7*3-2y=5

2y=21-5

2y=16

y=16/2=8



Thus the unit digit of the number is 3 and ten's digit is 8.


=> Thus number is 83.
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