Question

two digit number is selected at random find the probability that it is multiple of 4 but not divisible by 5​

Answer 1

Answer:

There are 90 two digit numbers(99–9).

Out of this there are 30 numbers divisible by 3(33–3)

Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5.

Therefore, the favorable cases are 30–6=24.

Hence, the required probability is 24/90 = 4/15.

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