Question

Two digit number is six times the of its digits. If digit at units place is increased by 2 and tens digit reduced by 2, the number obtained is 4 times the sum of its digits​

Answer 1

Answer:

54

Step-by-step explanation:

Let units place digit y and tens place be x

A two digit number is six times the sum of its digits

So,---A

If the digit in the units place is increased by 2 and the digit in the tens place is decreased by 2 then the number so formed is 4 times the sum of its digits.

---B

Plot A and B on graph

-- Black line

---Red line

Intersection point provides the answer

So, intersection point  (5,4)

So,x=5 , y = 4

So, Original number is 54

Answer 2

Answer:

54

Step-by-step explanation:

let the units digit be x

and the tens digit be y

Therefore the no. is (10y + x)

now according to the question

10y + x = 6(x + y) ----1⃣

and

10(y - 2) + (x + 2) = 4(x + y) ----2⃣

Now from equation 1⃣ and 2⃣

we get

10y + x = 54

Hence the required no. is 54.