Question

two digit number is such that the product of the digits is 14 when 45 is added to the number the digits are reversed find the number​

Answer 1

Answer:

27

Step-by-step explanation:

let digit at unit place be x

and digit at tens place be y.

so two digit number become 10y+x.

according to first condition,

xy= 14

x=14/y

if in two digit number digits are reverse that number become 10x+y.

according to second condition,

10y+x+45= 10x+y

10y-y+45=10x-x

9y+45=9x

9x-9y=45

x-y=5 ( dividing by 9 to both sides )

substituting value of x in this equation,

14/y-y=5

14-y^2=5y

y^2+5y-14=0

y^2-2y+7y-14=0

y(y-2) +7(y-2) =0

(y+7)(y-2) =0

y+7=0 or y-2=0

y= -7 or y=2

digit can not be negative

so y=2

x-y=5

x-2=5

x=5+2

x=7

original number=10y+x

=10*2+7

=20+7

=27