Question

two digit number sum of its digit is7 of
the number is reversed the new numbers 28
greater than twice the the unit digit of the
original number


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Answer 1

Here, X is the one's digitand (7-X) is the tens digit which is why we multiply it with 10. Hence, the original number is 10(7-3)+3= 43.

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Answer 2

Gɪᴠᴇɴ :-

• In a two digit number sum of its digit is7 of the number is reversed the new numbers 28 greater than twice the the unit digit of the original number.

ᴛᴏ ғɪɴᴅ :-

• Original number
• Reversed number

sᴏʟᴜᴛɪᴏɴ :-

• Let the digit at tens place be x and ones place be y

then,

According to 1st condition :-

1. Tens place digit + Ones place digit = 7

• ➮ x + y = 7

• ➮ x = 7 - y. --(1)

According to 2nd condition :-

• Original number = (10x + y)
• Reversed number = (10y + x)

• Reversed number = 28 + 2(Unit digit)

• ➮ (10y + x) = 28 + 2(y)

• ➮ 10y + x = 28 + 2y

• ➮ 10y - 2y + x = 28

• ➮ 8y + x = 28

• ➮ x = 28 - 8y. --(2)

From (1) and (2) , we get,

• ➮ (7 - y) = (28 - 8y)

• ➮ 8y - y = 28 - 7

• ➮ 7y = 21

• ➮ y = 21/7

• ➮ y = 3

Put y = 3 in (1) , we get,

• ➮ x = 7 - y

• ➮ x = 7 - 3

• ➮ x = 4

Hence,

• Tens place digit = x = 4
• Ones place digit = y = 3

Therefore,

• Original number (10x + y) = 43
• Reversed number (10y + x) = 34