Math, asked by prinkle4255, 3 days ago

Two digit number the units digit is 2 more than ni8 of the tens digit the sum of the the digits is is 27 less than the number find the product of the digits of the number

Answers

Answered by shinganesarthak11
0

Step-by-step explanation:

The number is 10x+20+x=11x+20

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71 (11x+20)

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71 (11x+20)14x+14=11x+20

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71 (11x+20)14x+14=11x+203x+6

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71 (11x+20)14x+14=11x+203x+6x=2

The number is 10x+20+x=11x+20Sum of the digits =x+2+x=2x+2So, 2x+2= 71 (11x+20)14x+14=11x+203x+6x=2∴ the number =11x²+10=42

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