Question

two digits number is 3 more than four times the sum of the two digits.If x and y are the digits in the ten's and one's places respectively ,then algebraic representation of the given situation is
​

Answer 1

EXPLANATION.

Let the tens digit place be = x

Let the unit digit place be = y

original number = 10x + y

reversing number = 10y + x

To find the algebraic expression.

According to the question,

Conditions.

Two digit number is 3 more than 4 times

the sum of the two digit.

=> 10x + y = 3 + 4 ( 10x + y)

=> 10x + y = 3 + 40x + 4y

=> - 30x - 3y = 1

=> 10x + y = -1

Algebraic expression = 10x + y = -1

Answer 2

Answer:

10x + y = -1

Step-by-step explanation:

Assume that the ten's digit number be x and one's digit number be y.

Original Number: 10x + y

Two digits number is 3 more than four times the sum of the two digits.

As per given condition,

→ 10x + y = 3 + 4(10x + y)

Solve the bracket

→ 10x + y = 3 + 40x + 4y

→ 10x - 40x + y - 4y = 3

→ -30x - 3y = 3

Take -3 as common

→ -3(10x + y) = 3

→ 10x + y = -1

Hence, the algebraic representation of the given situation is 10x + y = -1.