Question

two diogonals of a recctangle are length (4x+1) cm and (2x+15)cm the value of x is​

Answer 1

Given : Two diagonals of a rectangle are (4x + 1)cm and (2x + 15)cm

Need to Find : Value of x.

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$\bold {\underline{ \bigstar \: According \: to \: the \: question \: : }}$

• We know that, diagonals of a rectangle are equal in length. So,

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$\sf : \implies \: 4x + 1 = 2x + 15$

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$\sf : \implies \: 4x - 2x = 15 - 1$

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$\sf : \implies \: 2x = 14$

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$\sf : \implies \: x = \cancel\dfrac{14}{2}$

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$\sf : \implies \: x = 7$

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❍ Put the value of x in the length of diagonal.

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• 4x + 1 = 4(7) + 1 = 28 + 1 = 29cm
• 2x + 15 = 2(7) + 15 = 29cm

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$\sf\therefore{\underline{Hence, \: the \: diagonals \: of \: the \: rectangle \: are \: \bold{29 \: cm} \: and \: \bold{29 \: cm} \: respectively.}}$