Two discs of same mass and same thickness have densities as 17 g/cm351g/cm 3. The ratio of their moment of inertia about their central axes is?????
Answers
Answered by
72
we know,
momentum of inertia of disc about its centre is given by
where r the radius of disc.
volume of disc = base area × thickness
V = πr² × L
so, mass of disc = density × volume
m = d × V = dπr²L
r² = M/dπL
so, I = M(M/dπL) = M²/dπL
so, here π, L are constant .
therefore, moment of inertia is inversely proportional to density of disc.
so, if mass and thickness of disc are same
then, ratio of their moment of inertia should be
=
momentum of inertia of disc about its centre is given by
where r the radius of disc.
volume of disc = base area × thickness
V = πr² × L
so, mass of disc = density × volume
m = d × V = dπr²L
r² = M/dπL
so, I = M(M/dπL) = M²/dπL
so, here π, L are constant .
therefore, moment of inertia is inversely proportional to density of disc.
so, if mass and thickness of disc are same
then, ratio of their moment of inertia should be
=
Answered by
1
Answer:
above given answer is correct
Explanation:
same can be asked with different values as 17g/cm3,51 g cm3....so here also same 51/17
so,it's a readymade Question.....by heart the way..
cheer up ..
good day...
all the best mate
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