Question

Two diseases are throw simoltaneously find the probability of getting (1) sum is 7 (2) sum is a prime number (3) sum is at least 9​

Answer 1

Step-by-step explanation:

1) when sum is 7

possible outcomes = 1,6 , 2,5 , 3,4 , 5,2 , 6,1 , 4,3

= 6 outcomes

probability = 6/36 = 1/6

2) possible outcomes = 1,1 , 1,2 , 1,4 , 1,6 , 2,1 , 2,3, 2,5 , 3,2 , 3,4 , 4,1 , 4,3 , 5,2 , 5,6

= 13 outcomes

probability = 13/36

3) possible outcomes = 3,6 , 4,5 , 4,6 , 5,4, 5,5 , 5,6

= 6 outcomes

probability = 6/36 = 1/6

Answer 2

Answer:

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