Two dissimilar charges of magnitude5μC
each are separated by a distance of 40cm, its electric dipole moment is
Answers
Answered by
0
Answer:
Explanation:
p=(5*10^-6 * 40 * 10^-2)/2
=100 * 10^-2 * 10^-6
p=10^-6
Answered by
0
Answer:
2 x 10^-6
Explanation:
electric dipole moment formula = qd
q = 5micro coulomb
= 5 x 10^-6
d = 40 CM
= 40 x 10^ -2
q x d = 5 x 10^-6 x 40 x 10^-2
= 200 x 10^-8
= 2 x 10^2 x 10^-8
= 2 x 10^-6
Similar questions