Question

Two dissimilar charges of magnitude5μC
 each are separated by a distance of 40cm, its electric dipole moment is​

Answer 1

Answer:

Explanation:

p=(5*10^-6 * 40 * 10^-2)/2

=100 * 10^-2 * 10^-6

p=10^-6

Answer 2

Answer:

2 x 10^-6

Explanation:

electric dipole moment formula = qd

q = 5micro coulomb

= 5 x 10^-6

d = 40 CM

= 40 x 10^ -2

q x d = 5 x 10^-6 x 40 x 10^-2

= 200 x 10^-8

= 2 x 10^2 x 10^-8

= 2 x 10^-6